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ID#5640 HSC Physics 1st MCQ (Dhaka 2025)

দোলকটির দোলনকাল 2 sec এবং g = 9.8 ms⁻² হলে কার্যকরী দৈর্ঘ্য কত?
ক) 1.56 m
খ) 1.03 m
গ) 0.99 m
ঘ) 0.49 m

ব্যাখ্যা

$T = 2pi\sqrt{\frac{L}{g}} \implies L = \frac{gT^2}{4pi^2}$
$L = \frac{9.8 \times 2^2}{4 \times (3.1416)^2} \approx 0.9929 m$
Resource Details
Exam HSC
Subject Physics 1st paper
Chapter 8
Board Dhaka
Year 2025

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