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ID#5719 HSC Physics 1st MCQ (Jessore 2025)

একটি গ্রহের g' = g/6 এবং R' = R/4 হলে উক্ত গ্রহে মুক্তিবেগ কত?
ক) 0.56 km/s
খ) 0.80 km/s
গ) 2.286 km/s
ঘ) 2.50 km/s

ব্যাখ্যা

$v_e = \sqrt{2g'R'} = \sqrt{2 \times \frac{g}{6} \times \frac{R}{4}} = \sqrt{\frac{2gR}{24}} = \frac{11.2}{\sqrt{24}} \approx 2.286 kms^{-1}$।
Resource Details
Exam HSC
Subject Physics 1st paper
Chapter 6
Board Jessore
Year 2025

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