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ID#5769 HSC Physics 1st MCQ (Barisal 2025)

r=600m, v=90km/h, d=2m হলে বাইরের পাতটি কত উঁচু (h) হতে হবে?
ক) 0.21 m
খ) 18.87 m
গ) 18.97 m
ঘ) 21 m

ব্যাখ্যা

$\tan\theta \approx \frac{h}{d} = \frac{v^2}{rg} \implies h = \frac{d v^2}{rg}$
$h = \frac{2 \times 25^2}{600 \times 9.8} = \frac{1250}{5880} \approx 0.21 m$।
Resource Details
Exam HSC
Subject Physics 1st paper
Chapter 4
Board Barisal
Year 2025

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