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ID#5781 HSC Physics 1st MCQ (Barisal 2025)

একটি সেকেন্ড দোলকের কার্যকরী দৈর্ঘ্য (L) হলো—
ক) g/π
খ) π²/g
গ) g/π²
ঘ) gπ²

ব্যাখ্যা

সেকেন্ড দোলকের $T = 2$।
$2 = 2pi\sqrt{L/g} \implies 1 = \pi^2 L/g \implies L = g/\pi^2$।
Resource Details
Exam HSC
Subject Physics 1st paper
Chapter 8
Board Barisal
Year 2025

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