$\frac{d}{dx}(\tan^{-1}(e^x)) = কত?$ $\frac{e^x}{1 + e^{x^2}}$ $\frac{1}{1 + e^x}$ $\frac{e^x}{1 + e^{2x}}$ $\frac{1}{1 + e^{2x}}$

ID#6873 HSC Higher Math 1st MCQ (Dhaka 2023)

$\frac{d}{dx}(\tan^{-1}(e^x)) = কত?$

ক) $\frac{e^x}{1 + e^{x^2}}$

খ) $\frac{1}{1 + e^x}$

গ) $\frac{e^x}{1 + e^{2x}}$

ঘ) $\frac{1}{1 + e^{2x}}$

গ

একটানা সকল প্রশ্নের সমাধান পড়ুন

Resource Details

You must be logged in to post a comment or ask a question.

No discussion yet. Be the first to post a comment!